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	<title>麦特客 &#187; Probability</title>
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		<title>Regression using SPSS &#8211; A suburban hotel derives its gross income from its hotel and restaurant operations.</title>
		<link>http://www.matke.com/regression-using-spss-a-suburban-hotel-derives-its-gross-income-from-its-hotel-and-restaurant-operations/</link>
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		<pubDate>Thu, 29 Jul 2010 15:21:00 +0000</pubDate>
		<dc:creator>admin</dc:creator>
				<category><![CDATA[Probability]]></category>
		<category><![CDATA[SPSS]]></category>

		<guid isPermaLink="false">http://www.matke.com/?p=14</guid>
		<description><![CDATA[A suburban hotel derives its gross income from its hotel and restaurant operations. The owners are interested in the relationship between the number of rooms occupied on a nightly basis and the revenue per day in the restaurant. Below is a sample of 25 days (Monday through Thursday) from last year showing the restaurant income [...]]]></description>
			<content:encoded><![CDATA[<p>A suburban hotel derives its gross income from its hotel and restaurant operations. The owners are interested in the relationship between the number of rooms occupied on a nightly basis and the revenue per day in the restaurant. Below is a sample of 25 days (Monday through Thursday) from last year showing the restaurant income and number of rooms occupied.<br />
<table border="0" cellspacing="0" cellpadding="0">
<tbody>
<tr>
<td valign="bottom">
<p>Day</p>
</td>
<td valign="bottom">
<p>Income</p>
</td>
<td valign="bottom">
<p>Occupied</p>
</td>
</tr>
<tr>
<td valign="top">
<p>1</p>
</td>
<td valign="top">
<p>$1,452</p>
</td>
<td valign="top">
<p>23</p>
</td>
</tr>
<tr>
<td valign="top">
<p>2</p>
</td>
<td valign="top">
<p>1,361</p>
</td>
<td valign="top">
<p>47</p>
</td>
</tr>
<tr>
<td valign="top">
<p>3</p>
</td>
<td valign="top">
<p>1,426</p>
</td>
<td valign="top">
<p>21</p>
</td>
</tr>
<tr>
<td valign="top">
<p>4</p>
</td>
<td valign="top">
<p>1,470</p>
</td>
<td valign="top">
<p>39</p>
</td>
</tr>
<tr>
<td valign="top">
<p>5</p>
</td>
<td valign="top">
<p>1,456</p>
</td>
<td valign="top">
<p>37</p>
</td>
</tr>
<tr>
<td valign="top">
<p>6</p>
</td>
<td valign="top">
<p>1,430</p>
</td>
<td valign="top">
<p>29</p>
</td>
</tr>
<tr>
<td valign="top">
<p>7</p>
</td>
<td valign="top">
<p>1,354</p>
</td>
<td valign="top">
<p>23</p>
</td>
</tr>
<tr>
<td valign="top">
<p>8</p>
</td>
<td valign="top">
<p>1,442</p>
</td>
<td valign="top">
<p>44</p>
</td>
</tr>
<tr>
<td valign="top">
<p>9</p>
</td>
<td valign="top">
<p>1,394</p>
</td>
<td valign="top">
<p>45</p>
</td>
</tr>
<tr>
<td valign="top">
<p>10</p>
</td>
<td valign="top">
<p>1,459</p>
</td>
<td valign="top">
<p>16</p>
</td>
</tr>
<tr>
<td valign="top">
<p>11</p>
</td>
<td valign="top">
<p>1,399</p>
</td>
<td valign="top">
<p>30</p>
</td>
</tr>
<tr>
<td valign="top">
<p>12</p>
</td>
<td valign="top">
<p>1,458</p>
</td>
<td valign="top">
<p>42</p>
</td>
</tr>
<tr>
<td valign="top">
<p>13</p>
</td>
<td valign="top">
<p>1,537</p>
</td>
<td valign="top">
<p>54</p>
</td>
</tr>
<tr>
<td valign="top">
<p>14</p>
</td>
<td valign="top">
<p>$1,425</p>
</td>
<td valign="top">
<p>27</p>
</td>
</tr>
<tr>
<td valign="top">
<p>15</p>
</td>
<td valign="top">
<p>1,445</p>
</td>
<td valign="top">
<p>34</p>
</td>
</tr>
<tr>
<td valign="top">
<p>16</p>
</td>
<td valign="top">
<p>1,439</p>
</td>
<td valign="top">
<p>15</p>
</td>
</tr>
<tr>
<td valign="top">
<p>17</p>
</td>
<td valign="top">
<p>1,348</p>
</td>
<td valign="top">
<p>19</p>
</td>
</tr>
<tr>
<td valign="top">
<p>18</p>
</td>
<td valign="top">
<p>1,450</p>
</td>
<td valign="top">
<p>38</p>
</td>
</tr>
<tr>
<td valign="top">
<p>19</p>
</td>
<td valign="top">
<p>1,431</p>
</td>
<td valign="top">
<p>44</p>
</td>
</tr>
<tr>
<td valign="top">
<p>20</p>
</td>
<td valign="top">
<p>1,446</p>
</td>
<td valign="top">
<p>47</p>
</td>
</tr>
<tr>
<td valign="top">
<p>21</p>
</td>
<td valign="top">
<p>1,485</p>
</td>
<td valign="top">
<p>43</p>
</td>
</tr>
<tr>
<td valign="top">
<p>22</p>
</td>
<td valign="top">
<p>1,405</p>
</td>
<td valign="top">
<p>38</p>
</td>
</tr>
<tr>
<td valign="top">
<p>23</p>
</td>
<td valign="top">
<p>1,461</p>
</td>
<td valign="top">
<p>51</p>
</td>
</tr>
<tr>
<td valign="top">
<p>24</p>
</td>
<td valign="top">
<p>1,490</p>
</td>
<td valign="top">
<p>61</p>
</td>
</tr>
<tr>
<td valign="top">
<p>25</p>
</td>
<td valign="top">
<p>1,426</p>
</td>
<td valign="top">
<p>39</p>
</td>
</tr>
</tbody>
</table>
<p>Use a statistical software package to answer the following questions.</p>
<p>a. Does the breakfast revenue seem to increase as the number of occupied rooms increases? Draw a scatter diagram to support your conclusion. </p>
<p>b. Determine the coefficient of correlation between the two variables. Interpret the value. </p>
<p>c. Is it reasonable to conclude that there is a positive relationship between revenue and occupied rooms? Use the .10 significance level. </p>
<p>d. What percent of the variation in revenue in the restaurant is accounted for by the number of rooms occupied?</p>
<h5>Answer</h5>
<p>(A)</p>
<p><a href="http://www.matke.com/wp-content/uploads/2010/07/OUTPUT0.jpg"><img style="border-right-width: 0px; display: inline; border-top-width: 0px; border-bottom-width: 0px; border-left-width: 0px" title="OUTPUT0" border="0" alt="OUTPUT0" src="http://www.matke.com/wp-content/uploads/2010/07/OUTPUT0_thumb.jpg" width="624" height="500" /></a> </p>
<p> (B)   <br />r = 0.44, there is a WEAK positive correlation.   <br />(C)   <br />df = n-2 = 25-2 = 23   <br />α = 0.05   <br />one-tailed critical value T = 1.319   <br />Test statistic T = r*Sqrt[(n-2)/(1-r²)] = 0.44*Sqrt[(25-2)/(1-0.44²)] = 2.35   <br />Conclusion: Since 2.35 &gt; 1.319 we conclude that there is a positive relationship between the variables.   <br />(D)   <br />r² = 0.44² = 0.1936, so approximately 19% of the variation in revenue is explained by the variation in the number of rooms occupied.  </p>
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		<item>
		<title>Coins, dice, probability</title>
		<link>http://www.matke.com/coins-dice-probability/</link>
		<comments>http://www.matke.com/coins-dice-probability/#comments</comments>
		<pubDate>Sun, 09 May 2010 13:40:00 +0000</pubDate>
		<dc:creator>admin</dc:creator>
				<category><![CDATA[Probability]]></category>

		<guid isPermaLink="false">http://www.matke.com/?p=9</guid>
		<description><![CDATA[1)Three dice are thrown simultaneously. The probability of obtaining a sum of 6 is? 1)1/24&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160; 2)5/108&#160;&#160;&#160;&#160;&#160;&#160;&#160; 3)1/54&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160; 4)7/216 2)A coin is tossed 3 times. The probability of getting head and tail alternately is? 1)1/6&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160; 2)1/8&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160; 3)1/4&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160; 4)1/3 3)Three dice are thrown simultaneously. The probability of obtaining a multiple of 5? 1)1/36&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160; 2)5/108&#160;&#160;&#160;&#160;&#160;&#160;&#160; 3)1/54&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160; 4)43/216 Answer： [...]]]></description>
			<content:encoded><![CDATA[<h3>1)Three dice are thrown simultaneously. The probability of obtaining a sum of 6 is?</h3>
<p>1)1/24&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160; 2)5/108&#160;&#160;&#160;&#160;&#160;&#160;&#160; 3)1/54&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160; 4)7/216</p>
<h3>2)A coin is tossed 3 times. The probability of getting head and tail alternately is?</h3>
<p>1)1/6&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160; 2)1/8&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160; 3)1/4&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160; 4)1/3</p>
<h3>3)Three dice are thrown simultaneously. The probability of obtaining a multiple of 5?</h3>
<p>1)1/36&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160; 2)5/108&#160;&#160;&#160;&#160;&#160;&#160;&#160; 3)1/54&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160; 4)43/216</p>
<p>Answer：</p>
<p>1）</p>
<p>6=1+1+4，3 possible outcomes    <br />6=1+2+3，6possible outcomes     <br />6=2+2+2，1possible outcomes     <br />(3+6+1)/6*6*6=10/216 = 5/108</p>
<p>2）Here are the possible outcomes:    <br />HHH, HHT, HTH, HTT, TTT, TTH, THT, THH     <br />There are two outcomes that satisfy the alternate condition HTH and THT. Head and tail come alternatively in these two outcomes,     <br />Total possibilities=8     <br />Number of requirea outcome=2     <br />Probability=2/8=1/4     <br />So number 3) is correct answer</p>
<p>3/）</p>
<p>Maximum of three dice and 18    <br />So that may occur in multiples of 5 to 5,10,15     <br />As and when the 5: 5 = 1 +1 +3 will make arrangement with three kinds of 113     <br />5 = 1 + 2 + 2 will be ordered to do 122 with three kinds of     <br />And the time when 10 of 10 = 1 +3 +6 ordered to do 136 with 6     <br />10 = 1 +4 +5 ordered to do 145 with 6     <br />10 = 2 +2 +6 there are three kinds of ordered to do 226     <br />10 = 2 +3 +5 ordered to do 235 with 6     <br />10 = 2 +4 +4 there are three kinds of ordered to do 244     <br />10 = 3 +3 +4 there are three kinds of ordered to do 334     <br />When and when 15 = 3 +6 +6 15 366 do have three kinds of arrangement     <br />15 = 4 +5 +6 ordered to do 456 with 6     <br />15 = 5 +5 +5 555 ordered to do only one     <br />In summary there and in multiples of 5 3 +3 +3 +6 +6 +6 +6 +3 +3 +3 +1 = 43     <br />The vote occurred a total of three dice combination of a 6 * 6 * 6 = 216     <br />The probability is 43/216 = 43/216</p>
<p>right or wrong?</p>
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